xy=x^2+2y^2

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Solution for xy=x^2+2y^2 equation:


Simplifying
xy = x2 + 2y2

Solving
xy = x2 + 2y2

Solving for variable 'x'.

Reorder the terms:
xy + -1x2 + -2y2 = x2 + -1x2 + 2y2 + -2y2

Combine like terms: x2 + -1x2 = 0
xy + -1x2 + -2y2 = 0 + 2y2 + -2y2
xy + -1x2 + -2y2 = 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
xy + -1x2 + -2y2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
-1xy + x2 + 2y2 = 0

Move the constant term to the right:

Add '-2y2' to each side of the equation.
-1xy + x2 + 2y2 + -2y2 = 0 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-1xy + x2 + 0 = 0 + -2y2
-1xy + x2 = 0 + -2y2
Remove the zero:
-1xy + x2 = -2y2

The x term is xy.  Take half its coefficient (0.5y).
Square it (0.25y2) and add it to both sides.

Add '0.25y2' to each side of the equation.
-1xy + x2 + 0.25y2 = -2y2 + 0.25y2

Combine like terms: -2y2 + 0.25y2 = -1.75y2
-1xy + x2 + 0.25y2 = -1.75y2

Factor a perfect square on the left side:
(x + 0.5y)(x + 0.5y) = -1.75y2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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